2[x-(1-3x)]=3(x+1)

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Solution for 2[x-(1-3x)]=3(x+1) equation:


Simplifying
2[x + -1(1 + -3x)] = 3(x + 1)
2[x + (1 * -1 + -3x * -1)] = 3(x + 1)
2[x + (-1 + 3x)] = 3(x + 1)

Reorder the terms:
2[-1 + x + 3x] = 3(x + 1)

Combine like terms: x + 3x = 4x
2[-1 + 4x] = 3(x + 1)
[-1 * 2 + 4x * 2] = 3(x + 1)
[-2 + 8x] = 3(x + 1)

Reorder the terms:
-2 + 8x = 3(1 + x)
-2 + 8x = (1 * 3 + x * 3)
-2 + 8x = (3 + 3x)

Solving
-2 + 8x = 3 + 3x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3x' to each side of the equation.
-2 + 8x + -3x = 3 + 3x + -3x

Combine like terms: 8x + -3x = 5x
-2 + 5x = 3 + 3x + -3x

Combine like terms: 3x + -3x = 0
-2 + 5x = 3 + 0
-2 + 5x = 3

Add '2' to each side of the equation.
-2 + 2 + 5x = 3 + 2

Combine like terms: -2 + 2 = 0
0 + 5x = 3 + 2
5x = 3 + 2

Combine like terms: 3 + 2 = 5
5x = 5

Divide each side by '5'.
x = 1

Simplifying
x = 1

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